0=2a^2-4*2a

Solution for 0=2a^2-4*2a equation:

0=2a^2-4*2a

We move all terms to the left:

0-(2a^2-4*2a)=0

We add all the numbers together, and all the variables

-(2a^2-4*2a)=0

We get rid of parentheses

-2a^2+4*2a=0

Wy multiply elements

-2a^2+8a=0

a = -2; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-2)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-2}=\frac{-16}{-4}
=+4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-2}=\frac{0}{-4}
=0
$